Uva 369 Solution

#include<iostream>
#include<iomanip>
#define L long double
using namespace std;
L e;
L anik(L c, L d)
{
    static double i = 0;
    if(d == 0)
        return 1;
    if(d == e)
    {
        return (c/d) * anik(c-1.0, d-1.0);
    }
    else
    {
        return (c/d) * anik(c-1.0, d-1.0);
    }
}
int main()
{
    L n, m, a;
    cout << fixed;
    cout << setprecision(0);
    while(cin >> n >> m)
    {
        if(n == 0 && m == 0)
            break;
        e = m;
        a = anik(n, m);
        cout << n << " things taken " << m <<  " at a time is " << a << " exactly." << endl;
    }

    return 0;
}