Array Queries : Solution
#include<bits/stdc++.h>
#define mx 100002
using namespace std;
int a[mx];
int tree[mx*3];
void initialize(int node, int s, int e)
{
if(s == e)
{
tree[node] = a[s];
return;
}
int left = node*2;
int right = node*2 + 1;
int mid = (s+e)/2;
initialize(left, s, mid);
initialize(right, mid+1, e);
tree[node] = min(tree[left], tree[right]);
}
int query(int node, int s, int e, int i, int j)
{
if(i > e || j < s)
return 10e6;
if(s >= i && e <= j)
return tree[node];
int left = node*2;
int right = node*2+1;
int mid = (s+e)/2;
int r1 = query(left, s, mid, i, j);
int r2 = query(right, mid+1, e, i, j);
return min(r1, r2);
}
int main()
{
int t, k = 1;
cin >> t;
while(t--)
{
int n, q;
cin >> n >> q;
for(int i=1; i<=n; i++)
cin >> a[i];
initialize(1, 1, n);
cout << "Case " << k++ << ":\n";
while(q--)
{
int i, j;
cin >> i >> j;
cout << query(1, 1, n, i, j) << "\n";
}
}
return 0;
}
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