Curious Robin Hood Solution
#include<bits/stdc++.h>
#define mx 100010
#define fast ios_base::sync_with_stdio(false);cin.tie(NULL);cout.tie(NULL);
using namespace std;
vector<int>a(mx), tree(mx*3);
void initialize(int node, int s, int e)
{
if(s == e)
{
tree[node] = a[s];
return;
}
int left = node*2;
int right = node*2+1;
int mid = (s+e)/2;
initialize(left, s, mid);
initialize(right, mid+1, e);
tree[node] = tree[left] + tree[right];
}
int query(int node, int s, int e, int i, int j)
{
if(i>e || j<s)
return 0;
if(s>=i && e<=j)
return tree[node];
int left = node*2;
int right = node*2+1;
int mid = (s+e)/2;
int r1 = query(left, s, mid, i, j);
int r2 = query(right, mid+1, e, i, j);
return (r1+r2);
}
void update(int node, int s, int e, int i, int x)
{
if(i>e || i<s)
return;
if(s>=i && e<=i)
{
tree[node] = x;
return;
}
int left = node*2;
int right = node*2+1;
int mid = (s+e)/2;
update(left, s, mid, i, x);
update(right, mid+1, e, i, x);
tree[node] = tree[left] + tree[right];
}
int main()
{
fast
int t, x = 1;
cin >> t;
while(t--)
{
int n, q;
cin >> n >> q;
for(int i=1; i<=n; i++)
cin >> a[i];
initialize(1, 1, n);
cout << "Case " << x++ << ":\n";
int i, j, k;
while(q--)
{
cin >> i;
if(i == 1)
{
cin >> j;
j++;
cout << a[j] << "\n";
a[j] = 0;
update(1, 1, n, j, 0);
}
else if(i == 2)
{
cin >> j >> k;
j++;
a[j] += k;
update(1, 1, n, j, a[j]);
}
else
{
cin >> j >> k;
j++, k++;
cout << query(1, 1, n, j, k) << "\n";
}
}
a.clear();
tree.clear();
}
return 0;
}
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